Distance from Jardim Okinagua to Nucleo Sao Vicente de Paulo

The distance from Jardim Okinagua to Nucleo Sao Vicente de Paulo is approximately 7.7 km / 4.8 mi (as the crow flies).

The following map shows the distance from Jardim Okinagua to Nucleo Sao Vicente de Paulo.

For more detailed information about any of the places please click on the place name:
• Jardim Okinagua
• Nucleo Sao Vicente de Paulo

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Current distance: Jardim Okinagua -> Nucleo Sao Vicente de Paulo
Show reverse: Nucleo Sao Vicente de Paulo -> Jardim Okinagua

DistanceRouteRoute by bikeRoute by foot